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P. 218
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206 MECHANICAL DENTISTRY AND METALLURGY. •
of g-old gives 144, which, divided hy 9, the weight of the
wliole mass, gives 16. Hence, an alloy prepared as above
is 16 carats fine."
To Reduce Gold to a Required Carat.—The proportion
may be expressed as follows :
"As the required carat is 24, so is the weight of the gold
used to the w^eig-ht of the alloyed mass when reduced. The
weight of gold subtracted from this gives the quantity of
alloy to be added.
"
For example, reduce 6 ounces of pure gold to 16 carats.
" The statement is expressed thus
:
16: 24: : 6 : 9.
" Six subtracted from 9 leaves 3, which is the quantity
of alloy to be added. From this is deduced the following :—
"
Rule.—Multiply 24 by the weight of pure gold used,
and divide the product by the required carat. The quotient
is the weight of the mass when reduced, from which sub-
tract the w^eight of the gold used, and the remainder is the
weight of alloy to be added."
To Raise Gold to a Higher Carat.—This may be done by
adding pure g'old or a gold alloy finer than that required.'
The principle of the rule may be set forth in the following
general expression :
"As the alloy in the required carat is to the alloy in
the given carat, so is the weight of the alloyed gold used
to the weight of the reduced alloy required. The principle
may be practically applied by the following:
"
Rule.—Multiply the weight of the alloyed gold used
by the number representing the proportion of alloy in the
given carat, and divide the product by that representing
the proportion of alloy in the required carat ; the quotient
is the w'eight of the mass when reduced to the required
carat by adding fine gold.
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—
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206 MECHANICAL DENTISTRY AND METALLURGY. •
of g-old gives 144, which, divided hy 9, the weight of the
wliole mass, gives 16. Hence, an alloy prepared as above
is 16 carats fine."
To Reduce Gold to a Required Carat.—The proportion
may be expressed as follows :
"As the required carat is 24, so is the weight of the gold
used to the w^eig-ht of the alloyed mass when reduced. The
weight of gold subtracted from this gives the quantity of
alloy to be added.
"
For example, reduce 6 ounces of pure gold to 16 carats.
" The statement is expressed thus
:
16: 24: : 6 : 9.
" Six subtracted from 9 leaves 3, which is the quantity
of alloy to be added. From this is deduced the following :—
"
Rule.—Multiply 24 by the weight of pure gold used,
and divide the product by the required carat. The quotient
is the weight of the mass when reduced, from which sub-
tract the w^eight of the gold used, and the remainder is the
weight of alloy to be added."
To Raise Gold to a Higher Carat.—This may be done by
adding pure g'old or a gold alloy finer than that required.'
The principle of the rule may be set forth in the following
general expression :
"As the alloy in the required carat is to the alloy in
the given carat, so is the weight of the alloyed gold used
to the weight of the reduced alloy required. The principle
may be practically applied by the following:
"
Rule.—Multiply the weight of the alloyed gold used
by the number representing the proportion of alloy in the
given carat, and divide the product by that representing
the proportion of alloy in the required carat ; the quotient
is the w'eight of the mass when reduced to the required
carat by adding fine gold.
